Asked by Anon

Given g(x) = (x + 5)(x2 - 6x + 13), find the one real zero of g(x):

I think it's -5

Find the two complex zeros of g(x):
Answered by Anon
*(x + 5)(x^2 - 6x + 13)
Answered by Reiny
correct for real root x = -5

for complex:
x^2 - 6x + 13 = 0
x =(6 ± √-16)/2
= (6 ± 4i)/2
= 3 ± 2i
There are no AI answers yet. The ability to request AI answers is coming soon!