y= [(x-3)/(x^2+1)]^2
I know that I would use the product rule on the whole equation inside the brackets. But would i also do the quotient rule bc of the division?
2 answers
Correction**** I would use the chain rule. not product rule
your "first line derivative" would be
dy/dx = 2[(x-3)/(x^2 + 1) ] [ (x^2+1)(1) - (x-3)(2x)]/(x^2 + 1)^2
dy/dx = 2[(x-3)/(x^2 + 1) ] [ (x^2+1)(1) - (x-3)(2x)]/(x^2 + 1)^2
1 answer