Asked by Mozes dixon
But aceeleration due to gravity is 1o m/s.....so if a boy of mass 8kg falls from rest from a height of 1oom neglecting air resistance calculate his total energy after fallin down a distance of 4om.....pls a detailed answer
Answers
Answered by
Damon
I call acceleration due to gravity 9.8 m/s^2
If you fall with no friction, part of the potential energy you had at the top
relative to the ground turns to kinetic energy, (1/2) m v^2
at any point in the fall:
(1/2) m v^2 + m g (height) = 8*9.8*100
HOWEVER
The TOTAL energy remains the same.
m g h = 8 * 9.8 * 100 Joules
If you fall with no friction, part of the potential energy you had at the top
relative to the ground turns to kinetic energy, (1/2) m v^2
at any point in the fall:
(1/2) m v^2 + m g (height) = 8*9.8*100
HOWEVER
The TOTAL energy remains the same.
m g h = 8 * 9.8 * 100 Joules
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