Asked by bob
what is the sum of the odd numbers 1-2009
Answers
Answered by
Reiny
number of terms ---- n
a=1
term(n) = a + (n-1)d
2009 = 1 + (n-1)2
2009 = 1 + 2n - 2
2n = 2010
n = 1005
sum = (1005/2) (1 + 2009) = 1010025
a=1
term(n) = a + (n-1)d
2009 = 1 + (n-1)2
2009 = 1 + 2n - 2
2n = 2010
n = 1005
sum = (1005/2) (1 + 2009) = 1010025
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