Asked by Summer
How many mL of a solution of NaOH with pH equal to 1.395 x 101 do you need to mix with pure water to obtain 399 mL of a final solution with pH equal to 9.066 ?
Answers
Answered by
DrBob222
pH 13.95; convert to H^+ by
pH = -log(H^+) and change to OH.
Then convert pH 9.066 to OH^- the same way.
mLsoln1 x Msoln1 = mLsoln2 x Msoln2.
pH = -log(H^+) and change to OH.
Then convert pH 9.066 to OH^- the same way.
mLsoln1 x Msoln1 = mLsoln2 x Msoln2.
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