New mean = 46 + 5 = 51
Variance is unchanged.
Z = (score-mean)/SD
Variance = SD^2
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.
a large no. of bonobos were found to be normally distributed with a mean of 46 and a variance equal to 9. if each of their scored is increased by 5 points, what percentage of the new scores is less than 50?
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