Asked by Jackie
What is the volume of 128 g of Oxygen at STP?... here's my work...
O=16
128/16= 8 moles
8(22.4) = 179.2 L
Where did i go wrong?
O=16
128/16= 8 moles
8(22.4) = 179.2 L
Where did i go wrong?
Answers
Answered by
DrBob222
1 mol of an ideal gas occupies 22.4 L at STP. You have how many moles O2? That is moles = grams/molar mass.
Answered by
jackie
So are u implying that the of moles of O2 is wrong? How do u calculate molar mass?
Answered by
DrBob222
Oxygen is a diatomic molecule. It exists as O2 and not O.
128g/32 = 4.00 moles.
4.00 x 22.4L/mol = 89.6 L.
128g/32 = 4.00 moles.
4.00 x 22.4L/mol = 89.6 L.
Answered by
DrBob222
Many of the gases are diatomic.
H2, N2, O2, F2, Cl2, Br2, I2 (Br and I are not gases though at STP). The noble gases of He, Ne, Ar, Kr, Xe are monatomic. S and P are S8 and P4; they are solids.
H2, N2, O2, F2, Cl2, Br2, I2 (Br and I are not gases though at STP). The noble gases of He, Ne, Ar, Kr, Xe are monatomic. S and P are S8 and P4; they are solids.
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