The energy stored in a capacitor with capacitance C, having an electric potential difference ΔV, is represented by W = 1/2 C ΔV2. One application of this is in the electronic photoflash of a strobe light, like the one in the figure below. In such a unit, a capacitor of 10.0 µF is charged to 340 V. Find the energy stored

asked by Cory

13 years ago

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1 answer

W = (1/2) C V^2

W = .5 * 10 * 10^-6 * 340^2

= .578 Joules

answered by Damon

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0

Question

The energy stored in a capacitor with capacitance C, having an electric potential difference ΔV, is represented by W = 1/2 C ΔV2. One application of this is in the electronic photoflash of a strobe light, like the one in the figure below. In such a unit, a capacitor of 10.0 µF is charged to 340 V. Find the energy stored

1 answer

W = (1/2) C V^2

W = .5 * 10 * 10^-6 * 340^2

= .578 Joules

Damon · Answer

W = (1/2) C V^2 W = .5 * 10 * 10^-6 * 340^2 = .578 Joules