Asked by Cory
The energy stored in a capacitor with capacitance C, having an electric potential difference ΔV, is represented by W = 1/2 C ΔV2. One application of this is in the electronic photoflash of a strobe light, like the one in the figure below. In such a unit, a capacitor of 10.0 µF is charged to 340 V. Find the energy stored
Answers
Answered by
Damon
W = (1/2) C V^2
W = .5 * 10 * 10^-6 * 340^2
= .578 Joules
W = .5 * 10 * 10^-6 * 340^2
= .578 Joules