Isosceles triangle ABC has vertices at A(0, 0), B(8, 0), and C(x, 12). The value of x could be

Answer 1

I guess AC = BC

d^2 = x^2 + 144 = (x-8)^2 + 144
x^2 -16 x + 64 = x^2
x = 64/16 = 4