Asked by Anonymous
Isosceles triangle ABC has vertices at A(0, 0), B(8, 0), and C(x, 12). The value of x could be
Answers
Answered by
Damon
I guess AC = BC
d^2 = x^2 + 144 = (x-8)^2 + 144
x^2 -16 x + 64 = x^2
x = 64/16 = 4
d^2 = x^2 + 144 = (x-8)^2 + 144
x^2 -16 x + 64 = x^2
x = 64/16 = 4
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.