Asked by Marianna
m2-5m-14=0
b2-4b+4=0
2m2+2m-12=0
8n2+7n-15=7
and the hardest!
k2-31-2k=-6-3k2-k
b2-4b+4=0
2m2+2m-12=0
8n2+7n-15=7
and the hardest!
k2-31-2k=-6-3k2-k
Answers
Answered by
MathGuru
Some points to remember:
1. Be sure to set your equations equal to 0.
2. See if the equation factors easily.
3. If it does, factor, then set each factor equal to 0.
4. Solve for the solutions.
Let's look at your first equation:
m^2 - 5m - 14 = 0
(I'm using ^2 to mean squared.)
This equation is already equal to 0.
Let's see if it factors easily:
(m - 7)(m + 2) = 0 (It does!)
Now let's set each factor equal to 0:
m - 7 = 0; m = 7
m + 2 = 0; m = -2
Check the solutions with the original equation by substituting the values you found for m. It always helps to check your work.
I hope this will help get you started.
1. Be sure to set your equations equal to 0.
2. See if the equation factors easily.
3. If it does, factor, then set each factor equal to 0.
4. Solve for the solutions.
Let's look at your first equation:
m^2 - 5m - 14 = 0
(I'm using ^2 to mean squared.)
This equation is already equal to 0.
Let's see if it factors easily:
(m - 7)(m + 2) = 0 (It does!)
Now let's set each factor equal to 0:
m - 7 = 0; m = 7
m + 2 = 0; m = -2
Check the solutions with the original equation by substituting the values you found for m. It always helps to check your work.
I hope this will help get you started.
Answered by
oliva
m2-5m-14=0
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