Question

yea it sais, three times one number added to another number is 18. twice the first number minus the other number is twelve.

find the numbers

Answer 1

x=first number
y=second number

3*x + y = 18
2*x - y = 12

You need to eliminate one of the variables and solve for the remaining one. In this problem, you can see that if the two equations are added together, the y variable is eliminated:

adding:
3x + y = 18
2x - y = 12
---------------
5x + 0y = 30
5x = 30
x=6

plug the known x value into either equation to solve for y.
taking the first one...
3*6 + y = 18
rearrange to get
y = 0

Answer 2

hey thx man, i messed up that one cause i though added to another number ment it goes before it