Asked by Kelsey

The standard enthalpy of formation of Al3-(aq) is -538.4kJ/mol. How much heat is evolved when 0.3724 g of Al(s) reacts with excess hydrochloric acid?
Answered by Kelsey
0.3724 g x 26.98MW = 10.05 mol
-538.4kJ x 10.05 mol = -5410 kJ/mol
5410 kJ/mol of heat is evolved?????
Answered by DrBob222
Do you mean Al^3+ and not Al^3-?
moles = grams/molar mass not grams x molar mass.
You need to write and balance an equation, also.
Answered by Kelsey
yes, Al3+ sorry. so the moles=.01380. Could you help with the equation?
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