Asked by Jordan
A spherical ballon is leaking air at 2 cubic inches per hour.l How fast is the ballons radisu chancing when the radisu si 3 inches.
Answers
Answered by
Steve
v = 4/3 pi r^3
dv/dt = 4pi r^2 dr/dt
-2 = 4pi*9 dr/dt
dr/dt = -2/36pi = -1/18pi = -.0177 in/hr
dv/dt = 4pi r^2 dr/dt
-2 = 4pi*9 dr/dt
dr/dt = -2/36pi = -1/18pi = -.0177 in/hr
Answered by
Reiny
What is a radisu?
Once I can understand as a typo, but twice ?
V= (4/3)πr^3
dV/dt = 4π r^2 dr/dt
-2 = 4π(9)dr/dt
etc.
Once I can understand as a typo, but twice ?
V= (4/3)πr^3
dV/dt = 4π r^2 dr/dt
-2 = 4π(9)dr/dt
etc.
Answered by
Jordan
Sorry about that Reiny. I have a quick question though, where does the 9 come from?
Answered by
Reiny
Notice both Steve and I have the same derivative equation of
dV/dt = 4π r^2 dr/dt
what is the value of r^2 when r = 3 ?
dV/dt = 4π r^2 dr/dt
what is the value of r^2 when r = 3 ?
Answered by
Jordan
Oh okay. I understand that, i was just not understand where the 9 came from, but i see now. Thank you both
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