Asked by FrustratedDad

please help me simplify
(8(x^3y^4)2)-2
Answered by drwls
Are the last 2's exponents? That would mean you want to know
[8(x^3y^4)^2]^-2
The +2 and -2 operations on (x^3y^4) would leave it unchanged, and leave you with
(1/64)(x^3y^4)
Answered by james b
The problem to solve is:
(8(x^3y^4)2)-2

Multiply 8 and
8*(x^3*y^4)2 evaluates to 64

Abort (8*(x^3*y^4)2)-2 evaluates to 64-64
The final answer is 64-64
Answered by FrustratedDad
The 2's are not exponents
Answered by FrustratedDad
Apologies to you and James B, I'm home from work now and just looked at the problem and the 2's are exponents.
Answered by FrustratedDad
Apologies, I'm home from work now and was able to look at the problem for myself and the 2's are exponents.
Answered by drwls
If the 2's are exponents, I stand by my original answer.
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