let the width of the walkway be x ft
dimensions of the whole thing = (25+2x) by (14+2x)
(25+2x)(14+2x) = 672
350 + 78x + 4x^2 - 672=0
4x^2 + 78x - 322 = 0
x = (-78 ± √11236)/8
= 3.5 or a negative
the width should be 3.5 ft
check:
length = 25+7 = 32
width = 14 + 7 = 21
32 x 21 = 672
can u please help me with this math problem. i don't get how to do this question.
Mrs. Mabie has a rectangle swimming pool that measures 25 feet by 14 feet. She wants to have a cement walkway installed around the perimeter of the pool. The combined area of the pool and walkway will be 672 square feet. What will be the width of the walkway?
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