Asked by Jason
A(n) 5 g bullet is fired into a 249 g block that
is initially at rest at the edge of a frictionless
table of height 1.7 m. The bullet remains in
the block, and after impact the block lands
1.6 m from the bottom of the table.
The acceleration of gravity is 9.8 m/s
Find the initial speed of the bullet.
Answer in units of m/s
is initially at rest at the edge of a frictionless
table of height 1.7 m. The bullet remains in
the block, and after impact the block lands
1.6 m from the bottom of the table.
The acceleration of gravity is 9.8 m/s
Find the initial speed of the bullet.
Answer in units of m/s
Answers
Answered by
drwls
Compute the horizontal velocity V2 of the block using the distance X that it lands away from the table. If T is the time it takes to fall 1.7 m,
V2 = X/T
You should know the formula for T.
If not, get it from
1.7 = (g/2)T^2
After you have computed V2, you can use conservation of momentuym to determine the bullet's velocity, V1.
0.005*V1 = (0.005 + 0.249)*V2
V2 = X/T
You should know the formula for T.
If not, get it from
1.7 = (g/2)T^2
After you have computed V2, you can use conservation of momentuym to determine the bullet's velocity, V1.
0.005*V1 = (0.005 + 0.249)*V2
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