Asked by hunter

a mover uses a ramp to pull a 1000 newton cart up to the floor of his truck 0.8 meters high if it takes a force or 200 newtons to pull the cart what is the length of the ramp

Answers

Answered by drwls
The answer depends upon the amount of friction. If there is no friction, they should have said so.

In the frictionless case,
(Force) x (ramp length) = (weight) x (height)

To approximate frictionless behavior, the cart should have well lubricated wheels.
Answered by Anonymous
200*0.8=160
Answered by tu madre
tu madre
Answered by Random guy
4m
Answered by Graham
First, calculate the Mechanical Advantage by using MA = effort / load where effort is 200N (using 200N of effort to pull the cart) and load is 1000N (the cart exerts a force of 1000N on the ramp - the ramps load). 200N / 1000N = 5. Then use the ideal mechanical advantage formula for a ramp: IMA = length / height where IMA is the MA that we just calculated - 5, and height is 0.8m. Set up the equation like this: 5 = length / 0.8m = 4m
Answered by Arnav
Graham is partially right. MA= LOAD/EFFORT which gives you 1000N/200N = 5. 200N/1000N= 0.2. So now, 5 = length / 0.8m. Multiply both sides by 0.8m in order to isolate length. 5 x 0.8m = length = 4m
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