Asked by Jane
Please explain how to solve:
1/3 = p-2/p+8
1/3 = p-2/p+8
Answers
Answered by
Reiny
Jane,
when you posted this same question earlier I pointed out the problems with your lack of brackets.
http://www.jiskha.com/display.cgi?id=1325816262
You did not reply even though
you appear to have fixed up the P and p variation.
So I will solve it the way you typed it, even though I think that is not the way the question was meant to be.
multiply each term by 3p
p = 3p^2 - 6 + 24p
3p^2 + 23p - 6 = 0
p = (-23 ± √601)/6
when you posted this same question earlier I pointed out the problems with your lack of brackets.
http://www.jiskha.com/display.cgi?id=1325816262
You did not reply even though
you appear to have fixed up the P and p variation.
So I will solve it the way you typed it, even though I think that is not the way the question was meant to be.
multiply each term by 3p
p = 3p^2 - 6 + 24p
3p^2 + 23p - 6 = 0
p = (-23 ± √601)/6
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