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Sue and Sean are having a tug of war by pulling on opposite ends of a 1.43 kg rope. Sue pulls with a 46.47 N force. What is Sean's force if the rope accelerates toward Sue at 4.92 m/s2
13 years ago

Answers

Henry
Fn = F1-F2 = ma,
F1-46.47 = 1.43 * 4.92,
Solve for F1, Sean's force.
13 years ago
Anonymous
53.5N
9 years ago

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