Asked by Hilary
In parallelogram DEFG, DH = x + 1, HF = 3y, GH = 3x – 4, and HE = 5y + 1. Find the values of x and y.
The parallelogram has D at the top left E at the top right, G at the bottom left and and F at the bottom right with H in the middle.
Thank You ^0^
The parallelogram has D at the top left E at the top right, G at the bottom left and and F at the bottom right with H in the middle.
Thank You ^0^
Answers
Answered by
Steve
Since the diagonals bisect each other,
x+1 = 3y
3x-4 = 5y+1
x - 3y = -1
3x - 5y = 5
3x - 9y = -3
3x - 5y = 5
4y = 8
y=2
x=5
x+1 = 3y
3x-4 = 5y+1
x - 3y = -1
3x - 5y = 5
3x - 9y = -3
3x - 5y = 5
4y = 8
y=2
x=5
Answered by
Hilary
THank You :) I appreciate your help! :)
Answered by
Kirito
x = 5 and y = 2 does not work, I have tried.
Answered by
try again kirito
yes it does work
Answered by
Surpise
It adds up 5+1=6
3 x 2=6
3(5)-4=11
5(2)+1=11
So they are correct.
3 x 2=6
3(5)-4=11
5(2)+1=11
So they are correct.
Answered by
Another Surprise
How'd he get x=5, though?
Answered by
hello
how did he get 9y
Answered by
Danny
Thanks Steve
Answered by
wow
holy crap it's been a decade and we're still struggling on the same exact questions
Answered by
sdjf
bruh this is trash, no wonder brainy is better
Answered by
Jimin's Jam's ♫
LOOOOOOL sdjf you funny and also right
Answered by
GeometryKindaSus
BROO why is this question even a thingg, ITS BEEN A DECADE AND WE STILL HAVENT GOT IT LOLL
Answered by
Kirby
X = 5
Y = 2
Y = 2
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