Asked by CRAig
The height h is the time of seconds that the ball has been in the air with an initial vertical velocity of 48 feet per second from a height of 5 feet above the ground is given by the equation
h=-16t^2 + 48t + 5
where t is the time in seconds that the ball has been in the air. After how many seconds in the ball at of 37 feet.
h=-16t^2 + 48t + 5
where t is the time in seconds that the ball has been in the air. After how many seconds in the ball at of 37 feet.
Answers
Answered by
Damon
I have not seen a gravity problem in feet instead of meters for a while.
37 = -16 t^2 + 48 t + 5
16 t^2 - 48 t + 32 = 0
t^2 - 3 t + 2 = 0
(t-2)(t-1) = 0
t = 1 or 2
so
the ball is at 37 feet after one second on the way up and at two seconds on the way down
37 = -16 t^2 + 48 t + 5
16 t^2 - 48 t + 32 = 0
t^2 - 3 t + 2 = 0
(t-2)(t-1) = 0
t = 1 or 2
so
the ball is at 37 feet after one second on the way up and at two seconds on the way down
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