Asked by Brett
1) Suppose the mass of the NaOH used in a reaction was doubled. What would you expect to happen to the heat given off by the reaction? Explain your answer.
2)Again, suppose the mass of the NaOH used in a reaction was doubled. What would you expect to happen to the heat given off per mole of NaOH in the reaction? Explain your answer.
I am not sure what the answer would be, however I do think that for question 1 the answer would be more and for question 2 the answer would be less. If I am right could you explain to me why those would be the answers as I do know the why and if I'm wrong explain what the right answer would be?
Thanks
2)Again, suppose the mass of the NaOH used in a reaction was doubled. What would you expect to happen to the heat given off per mole of NaOH in the reaction? Explain your answer.
I am not sure what the answer would be, however I do think that for question 1 the answer would be more and for question 2 the answer would be less. If I am right could you explain to me why those would be the answers as I do know the why and if I'm wrong explain what the right answer would be?
Thanks
Answers
Answered by
DrBob222
I may be reading the problem wrong but #2 seems to be stated in a peculiar fashion. I think the two questions are different and #2 doesn't follow from #1.
For #1, if q = mass x (delta H/gram) and you double grams, then q must double and the reaction will release more heat.
If I read #2 correctly, it wants to know, not how much heat is evolved if more NaOH is added, but how much heat is evolved per mole. Delta H/mol is a constant is it not so it makes no difference how much NaOH is added, the heat/mol will stay the same.
For #1, if q = mass x (delta H/gram) and you double grams, then q must double and the reaction will release more heat.
If I read #2 correctly, it wants to know, not how much heat is evolved if more NaOH is added, but how much heat is evolved per mole. Delta H/mol is a constant is it not so it makes no difference how much NaOH is added, the heat/mol will stay the same.
Answered by
Anonymous
The heat would remain the same
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