Question
Could someone give me an example of a linear eqution using elimination to solve the systems of equations?
Answers
Steve
2x + 7y = 16
x - 3y = -5
multiply the 2nd equation by 2
2x + 7y = 16
2x - 6y = -10
subtract the equations to eliminate x:
0x + 13y = 26
y = 2
so,
x = 1
x - 3y = -5
multiply the 2nd equation by 2
2x + 7y = 16
2x - 6y = -10
subtract the equations to eliminate x:
0x + 13y = 26
y = 2
so,
x = 1
Angel
Thanks!!!
Angel
What I don't get is that in my book the question is {2x - 3= - 5y and -2y = -3y + 1}. How do I put the question in standard form?
Angel
A little help, please!!! :-)
Steve
Just move all the x's and y's to one side, and the numbers to the other side:
2x - 3 = -5y
-2x = -3y + 1
becomes
2x + 5y = 3
-2x + 3y = 1
add them together to eliminate the x's
0x + 8y = 4
y = 1/2
so,
x = 1/4
If I misread -2y = -3y + 1 then you can surely fix it and get the expected answer.
2x - 3 = -5y
-2x = -3y + 1
becomes
2x + 5y = 3
-2x + 3y = 1
add them together to eliminate the x's
0x + 8y = 4
y = 1/2
so,
x = 1/4
If I misread -2y = -3y + 1 then you can surely fix it and get the expected answer.
Reiny
In most cases it is best to have the x's and y's on one side, with the constant on the other side
2x - 3 = -5y becomes
2x + 5y = 3
Your other equation probably has a typo, I was expecting an x term instead there are two y terms.
Anyway, get the x's and y's to the left, and the constant to the right.
Then proceed in the way that Steve illustrated above.
2x - 3 = -5y becomes
2x + 5y = 3
Your other equation probably has a typo, I was expecting an x term instead there are two y terms.
Anyway, get the x's and y's to the left, and the constant to the right.
Then proceed in the way that Steve illustrated above.