Asked by Rass

write the partial fraction decomposition of the following rational expression ( hint: binomial expansion with Pascal triangle can be used to expand binomials. technology may be used to solve large systems using matrices or determinants)

4
------------------------------------- x^3(x-3)(x+2)(x-1)^2(x^2+1)^2(x^2-1)^3

Answers

Answered by Reiny
Look how your expression turned out.

Use brackets and such symbols as / for division to type your expression.
Answered by Rass
this better?

write the partial fraction
decomposition of the following rational expression ( hint: binomial expansion with Pascal triangle can be used to expand binomials. technology may be used to solve large systems using matrices or determinants)

4/x^3(x-3)(x+2)(x-1)^2(x^2+1)^2(x^2-1)^3
Answered by Rass
Can anyone please help me?
Answered by Reiny
Are you serious?
Is this an actual question from a textbook?

Even Wolfram had a hemorrhage trying to do that one
Look at the "partial fraction expansion"
http://www.wolframalpha.com/input/?i=4%2F%28x%5E3%28x-3%29%28x%2B2%29%28x-1%29%5E2%28x%5E2%2B1%29%5E2%28x%5E2-1%29%5E3%29
Answered by Rass
Yes I am very serious. My math teacher must be playing a sick joke with us. He said it would hurt our brain. I guess he just wants us to know that there are such problems as this one that exists. thank you for your help though :)
Answered by Reiny
Do you realize the number of cases you can have
e.g.
A/x + B/x^2 + C/x^3 + D/(x-3) + E/(x+2) + F(x^2+1) + G/(x^2+1)^2 + ........

and we should not forget such fractions as
?/(x(x^2+1)) or ?/(x(x-3)(x+2)(x^2-1)^3 )

can you see the absurdity of this question?

There would be 12 different factors, which would make 2^12 - 1 or 4095 subsets
Answered by Rass
I see what you're saying. Thank you very much. there is no way to do this with binomial expansion though with the pascal triangle or it's still impoosibly long?
Answered by joe
10b-b+1
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