1. Solve (x+19)(x-11)(x+18)>0

Question

2. Solve the equation 2x^2-x=-7

Answer 1

1. (x+19)(x-11)(x+18) > 0
critical values are -19, 11 and -18

the corresponding cubic graph would have x-intercepts of -19, -18, and 11 , starting with +1x^3

so obviously the graph is above the x-axis for
-19 < x < -18 or x > 11

which would then be the solution for your inequation

2. 2x^2 - x + 7 = 0
by the formula
x = (1 ± √-55)/4
= (1 ± i√55)/4