Asked by Pinky P
1. Solve (x+19)(x-11)(x+18)>0
2. Solve the equation 2x^2-x=-7
2. Solve the equation 2x^2-x=-7
Answers
Answered by
Reiny
1. (x+19)(x-11)(x+18) > 0
critical values are -19, 11 and -18
the corresponding cubic graph would have x-intercepts of -19, -18, and 11 , starting with +1x^3
so obviously the graph is above the x-axis for
-19 < x < -18 or x > 11
which would then be the solution for your inequation
2. 2x^2 - x + 7 = 0
by the formula
x = (1 ± √-55)/4
= (1 ± i√55)/4
critical values are -19, 11 and -18
the corresponding cubic graph would have x-intercepts of -19, -18, and 11 , starting with +1x^3
so obviously the graph is above the x-axis for
-19 < x < -18 or x > 11
which would then be the solution for your inequation
2. 2x^2 - x + 7 = 0
by the formula
x = (1 ± √-55)/4
= (1 ± i√55)/4
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.