Question

If tan(xy) = x, then dy/dx =

Answer 1

wats your question?

Answer 2

d/dx (tan u) = sec^2 u du/dx
so
d/dx (tan xy) = sec^2 (xy) [x dy/dx + y]
so
sec^2(xy) [x dy/dx + y] = dx/dx = 1

sec^2(xy) x dy/dx = [1 - y sec^2(xy) ]

dy/dx = [1 - y sec^2(xy) ]/[x sec^2(xy)]

Answer 3

but sec^2 (xy) = 1/cos^2 (xy
so
dy/dx = [ cos^2(xy) - y ] / x

Answer 4

What are all values of k for which integral x^2 dx=0