Asked by Lily
The perimeter of triangle ABC is 29 meters. Line segment AD bisects angle A. Find AB and AC. CD=5cm, DB=4 cm.(triangle angle bisector theorem)
Answers
Answered by
Damon
AB/AC = 4/5 so AB = 4 AC/5
AB + AC + 9 = 29
so
AB + AC = 20
4 AC/5 + AC = 20
4 AC + 5 AC = 100
9 AC = 100
etc
AB + AC + 9 = 29
so
AB + AC = 20
4 AC/5 + AC = 20
4 AC + 5 AC = 100
9 AC = 100
etc
Answered by
Anonymous
AC= 11.11111111
AB= 8.888888889
AB= 8.888888889
Answered by
hey
You forgot to change 29m to 2900cm.
Answered by
Anonymous
*The problem should say 29 cm.
AB/AC=4/5, so 4AC=5AB, which is also 4/5(AC)=AB.
AB+BC+AC=29
AB+AC+9=29
AB+AC=20
4/5(AC)+AC=20
9/5(AC)=20
AC=11 1/9
AB=20-AC
AB=20-11 1/9
AB=8 8/9
AB/AC=4/5, so 4AC=5AB, which is also 4/5(AC)=AB.
AB+BC+AC=29
AB+AC+9=29
AB+AC=20
4/5(AC)+AC=20
9/5(AC)=20
AC=11 1/9
AB=20-AC
AB=20-11 1/9
AB=8 8/9
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