Asked by TIFFANY
The radius in meters of a circular oil slick increases at a rate of (12 - 0.3t), where t is measured in hours. Which of the following expressions would calculate the rate at which the area of the oil slick is increasing when the radius is 100 meters?
Answers
Answered by
Damon
dr/dt = (12 - .3 t)
a = pi r^2
da/dt = 2 pi r dr/dt
da/dt = 2 pi r (12-.3 t)
when r = 100
da/dt = 200 pi (12 - .3 t)
a = pi r^2
da/dt = 2 pi r dr/dt
da/dt = 2 pi r (12-.3 t)
when r = 100
da/dt = 200 pi (12 - .3 t)
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