Asked by Nicole
I want to know why [5-5cos(square)(filter)] is equal to [5sin(square)(filter)]
Do you guys know what I mean? sorry for that I can't type (square and filter) signs
Do you guys know what I mean? sorry for that I can't type (square and filter) signs
Answers
Answered by
Reiny
First of all, what is this "filter" you are talking about?
Is "filter"supposed to be a variable.
I will assume that it is, and will replace it with x
so you state
5 - 5cos √x = 5sin √x
Secondly, this is not true for all x's as you state.
All I need in one counterexample to show the equation is not true as an identity.
e.g. let x = .25
LS = 5 - 5cos √.25
= 5 - 5cos .5
= .621...
RS = 5sin √.25
= 5sin .5 = 2.39...
Are you solving the equation?
Let me know before I get into that.
Is "filter"supposed to be a variable.
I will assume that it is, and will replace it with x
so you state
5 - 5cos √x = 5sin √x
Secondly, this is not true for all x's as you state.
All I need in one counterexample to show the equation is not true as an identity.
e.g. let x = .25
LS = 5 - 5cos √.25
= 5 - 5cos .5
= .621...
RS = 5sin √.25
= 5sin .5 = 2.39...
Are you solving the equation?
Let me know before I get into that.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.