Asked by guru

The length of the fence of a trapezium-shaped field ABCD is 130m and side AB is perpendicular to each of the parallel sides AD and Bc.if BC=54m,CD=19m and AD=42m,find the area of the field.
Answered by Steve
The only missing side is AB

AB + 54 + 19 + 42 = 130
AB = 15

That's the height. So area

a = 15 * (54+52)/2
Answered by Henry
post it.
Answered by tanmay
in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.
Answered by tanmay
in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.
Answered by harsh
in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

Answered by pawan
720m
Answered by Manjari
donot know
Answered by Anonymous
Find the area if ab =31 a



Answered by jeet
720
Answered by Yaminee
795 m2
Answered by aditi singh
720m2
Answered by Anonymous
720msq
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