Asked by Da S
Adam and Rahmad shared some beads.if Adam gave one-third of his share to Rahmad,Rahmad would have 70 more than Adam.if Adam gave one-fifth of his share to rahmad,Rahmad would have 10 more Adam.how many beads does Adam have at first?
Answers
Answered by
Steve
If Adam gave 1/3 of his beads to Rahmad, he'd have 2/3 left. so,
2a/3 + 70 = r + a/3
4a/5 + 10 = r + a/5
a/3 - r = -70
3a/5 - r = -10
4a/15 = 60
a = 225
220 = r+75
r = 145
so, if adam gives 1/3 to rahmad,
a has 150 and r has 220
if adam gives 1/5,
a has 180 and r has 190
2a/3 + 70 = r + a/3
4a/5 + 10 = r + a/5
a/3 - r = -70
3a/5 - r = -10
4a/15 = 60
a = 225
220 = r+75
r = 145
so, if adam gives 1/3 to rahmad,
a has 150 and r has 220
if adam gives 1/5,
a has 180 and r has 190
Answered by
Anonymous
225
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