Asked by TRACY

The sum of four consecutive integers is at least 114. Find the smallest possible values for these numbers.

HOW YOU DO THIS?
Answered by Ms. Sue
Let x = first integer
Then x + 2 = next integer
x + 4 = third integer
x + 6 = fourth consecutive integer

x + x + 2 + x + 4 + x + 6 > 114

4x + 12 > 114

4x > 102
Answered by Lisa
thanks
Answered by RAY
so the first number would be 25.50
then 2nd would be 27.50
Answered by Ms. Sue
Ray -- that can't be right. The directions state that these are EVEN numbers.

Answered by TRACY
is that correct
Answered by TRACY
i don't get tell me please
Answered by Ms. Sue
102 / 4 = 25.5

The nearest even number is 26. That must be the

Check it out: 26 + 28 + 30 + 32 = ?

Aren't these the smallest possible values for these numbers?

Answered by RAY
yea you had to round
Answered by TRACY
But look consecutive numbers are Numbers which follow each other in order, without gaps, from smallest to largest.

12, 13, 14 and 15 are consecutive numbers.

THEY ARE NOT EVEN
Answered by TRACY
IT SHOULD BE WITHOUT GAPS
Answered by Ms. Sue
I'm sorry. I thought they were supposed to be even numbers. I apologize.

You're right, there should be no gaps.

Answered by Ms. Sue
Let's start again. (I think I've read the problem correctly this time.)

x + x + 1 + x + 2 + x + 3 > 114

4x + 6 > 114

4x > 108

x = 27

Check: 27 + 28 + 29 + 30 = 114

Answered by TRACY
thank you
Answered by Ms. Sue
You're welcome.

And again -- I'm sorry I steered you wrong.

The few times I taught math, I offered my students extra credit whenever they saw that I'd made a stupid mistake like this.

There are no AI answers yet. The ability to request AI answers is coming soon!