Asked by TRACY
I'm really confused how you do this
Two unequal semicircles, a square , and a rectangle are joined. If the dimensions of the rectangle are 8in by 16in, find the are of the entire region to the nearest 10th.
theres a rectangle in the middle and semi circle on top and side
Two unequal semicircles, a square , and a rectangle are joined. If the dimensions of the rectangle are 8in by 16in, find the are of the entire region to the nearest 10th.
theres a rectangle in the middle and semi circle on top and side
Answers
Answered by
Reiny
I sketched it the following way:
a square joined to the width of the rectangle on the left side
A semi-circle on top with diameter along the length of the rectangle.
A semi-circle at the right side of the rectangle with diameter along the width of the rectangle.
Area of square = 64
area of rectangle = 128
area of small sem-circle = (1/2)π(4^2) = 8π
area of large semi-circle = (1/2)π(8^2) = 32π
total = 64+128+8π+32π = .....
a square joined to the width of the rectangle on the left side
A semi-circle on top with diameter along the length of the rectangle.
A semi-circle at the right side of the rectangle with diameter along the width of the rectangle.
Area of square = 64
area of rectangle = 128
area of small sem-circle = (1/2)π(4^2) = 8π
area of large semi-circle = (1/2)π(8^2) = 32π
total = 64+128+8π+32π = .....
Answered by
TRACY
the answer is 192 + 40pie
that equals 317.6 inches square
that equals 317.6 inches square
Answered by
Reiny
correct
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