find f"(x) if f(x)= cube root(x^2-2x+1)

Answer 1

Note that x^2 - 2x + 1 = (x-1)^2
f(x) = (x-1)^2/3
f' = 2/3 (x-1)^-1/3
f'' = -2/9 (x-1)^-4/3