Asked by Catherine
What is the concentration (m) of a solution that consists of 48 grams of copper (2) acetate dissolved in 645 mL of solution?
Answers
Answered by
Steve
What's the formula for copper(2) acetate?
Cu(CH3CO2)2
Now, what's the mol weight?
Cu = 63.55
C = 12.01
H = 1.008
O = 16.00
so, 1 mol = 63.55 + 2(12.01 + 3.024 + 12.01 + 32) = 181.638
Now things get easy.
You have 48/181.638 = 0.264 mol of cupric acetate
so, your solution is .264mol/.645L = .409M
Cu(CH3CO2)2
Now, what's the mol weight?
Cu = 63.55
C = 12.01
H = 1.008
O = 16.00
so, 1 mol = 63.55 + 2(12.01 + 3.024 + 12.01 + 32) = 181.638
Now things get easy.
You have 48/181.638 = 0.264 mol of cupric acetate
so, your solution is .264mol/.645L = .409M
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.