65.25 grams of NaC2H3O2 in 1115 mL of solution.

Answer 1

I don't see a question. Do you want to know the molarity?
65.25/82 = 0.787 mols.
M = mols/L = 0.787/1.115 L = ? M

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Answer 2

Please disregard these Greek letters.
<&pi><&Delta><&lambda>