2NH3 + O2 → N2 + 3H2O
Note that you need 2 moles of NH3 for each mole of O2
So, you'd need 2.275 mol of O2
Balance the equation
NH3 + O2 −→ N2 + H2O
Given 4.55 mol of the reactant NH3, determine the corresponding amount of O2.
1 answer