Asked by Elli
Verify if question a is correct I calcuated twice now and I am getting 0 as an answer.
I don't understand question b
a) Examine the function f9x) =2(0.5x-1)^2(x+2)^2. Determine the function's average of change from -2<x<2.
I got answer:
=0-0/-2-2
=0
Avg rate of change: 0
b) Explain how why you could have predicted what the average rate of change would have been without doing any computations
I don't understand question b
a) Examine the function f9x) =2(0.5x-1)^2(x+2)^2. Determine the function's average of change from -2<x<2.
I got answer:
=0-0/-2-2
=0
Avg rate of change: 0
b) Explain how why you could have predicted what the average rate of change would have been without doing any computations
Answers
Answered by
Reiny
the equation was f(x) = 2(.5x-1)^2 (x+2)^2
Quick observation is that for x=-2 the first factor is zero and for x = +2 the second factor is zero.
In either case f(x) = 0 or y = 0 for those two end values.
"Without any calculation" ?, I had to calculate the value inside the brackets.
Quick observation is that for x=-2 the first factor is zero and for x = +2 the second factor is zero.
In either case f(x) = 0 or y = 0 for those two end values.
"Without any calculation" ?, I had to calculate the value inside the brackets.
Answered by
Elli
So, question a is correct right? The answer is 0?
As for question b, the question is wrong? there is no way to predict the average rate of change unless you calculate inside the bracketS?
As for question b, the question is wrong? there is no way to predict the average rate of change unless you calculate inside the bracketS?
Answered by
Reiny
yes, the average rate of change is 0
as for b), I don't say the "question is wrong", all I meant was that you had to do a bit of "calculation" to realize that the brackets were zero.
as for b), I don't say the "question is wrong", all I meant was that you had to do a bit of "calculation" to realize that the brackets were zero.
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