Please write y=-x62-2x+3 in vertex form. Help would be appreciated thank you :)

Answer 1

y = -x^2 - 2x + 3
y = -(x^2 + 2x) + 3
now add 1 in the parens to make a perfect square

y = -(x^2 + 2x + 1) + 1 + 3
y = -(x+1)^2 + 4
y-4 = -(x+1)^2

For y-k = a(x-h)^2
the vertex is at (h,k)

so, your vertex is at (-1,4)