Asked by Zee
Please Help. A 5 kg object is propelled from rest at time t=0 by a net force F that always acts in the same direction. The magnitude of F in newtons is given as a function of t in seconds by F= 0.5t. What is the speed of the object at t =4s?
Answers
Answered by
bobpursley
F=ma
.5t=m a
v= ds/dt
a= dv/dt
v= int a dt= int F/mass dt= INT .5t/m dt
v= 1/4 4^2/m=4/5 m/s check that.
.5t=m a
v= ds/dt
a= dv/dt
v= int a dt= int F/mass dt= INT .5t/m dt
v= 1/4 4^2/m=4/5 m/s check that.
Answered by
Allan taha
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