Two forces are pushing on an object, one at 12 lbs of Force and one at 5.66 lbs of Force. The angle between them is 35° (each is 72.5 from horizontal, such that the forces make a v with the object in the center).

Question

17. What is the total Force on the object?


18. What is the smallest angle of the triangle?


19. What is the largest angle in the triangle?


20. What is the remaining angle of the triangle?

Answer 1

I assume you constructed a parallelogram so that the diagonal is the resultant of the two forces
The obtuse angle would then be 180-35 = 145°

Use the cosine law to find the magnitude |r| of that resultant
|r|^2 = 5.66^2 + 12^2 - 2(12)(5.66)cos 145°
= 287.309
|r| = 16.95

"What is the smallest angle of the triangle", I will assume we are looking at the triangle just dealt with above ...
The smallest angle will be opposite the smallest side, let it be Ø
sinØ/5.66 = sin 145/16.95
sinØ = .19153..
Ø = 11.04°

easy to find the third angle