Asked by Kyle

The 17500 Hz whine of the turbines in the jet engines of an aircraft moving with speed 280 m/s is heard at what frequency by the pilot of a second craft trying to overtake the first at a speed of 380 m/s?
Answered by Henry
F = ((V+Vr)/(V+Vs))*Fs,

V = 343 m/s = Speed of sound in air.
Vr = 380 m/s = Speed of receiver.
Vs = 280 m/s = Speed of source.
Fs = 17,500 Hz. = Frequency of source.

F = 20,309 Hz.

Plug-in the given values to verify results.





f
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