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The cost, in millions, to remove x% of pollution in a pond is modeled by the equation: C=6350/(425-3x) . What is the cost to re...Asked by Ashley A.
The cost, in millions, to remove x% of pollution in a pond is modeled by the equation:
C=6350/(425-3x)
.
What is the cost to remove 75% of the pollution?
Hint: Plug in and calculate, do not convert to a decimal.
Can someone tell me how figure this out step by step recheck my answer PLEASEEEEEE!!! I tried to recheck AND IT DIDN'T COME UP WITH SAME Answer due tommorrow help me please
cost = 6350/(425 - 3(.25)) =$ 14.967
it would cost about $15 million
C=6350/(425-3x)
.
What is the cost to remove 75% of the pollution?
Hint: Plug in and calculate, do not convert to a decimal.
Can someone tell me how figure this out step by step recheck my answer PLEASEEEEEE!!! I tried to recheck AND IT DIDN'T COME UP WITH SAME Answer due tommorrow help me please
cost = 6350/(425 - 3(.25)) =$ 14.967
it would cost about $15 million
Answers
Answered by
bobpursley
you should have 75 in the denominator, not .25
cost = 6350/(425-225)= you do it.
cost = 6350/(425-225)= you do it.
Answered by
Ashley A.
The answer would be 31.496 AM I CORRECT IT WOULD COST ABOUT 31 MILLION
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