Asked by Hannah
The radius of the Earth is approximately 6000 km. The acceleration of an astronaut in a perfectly circular orbit 300 km above the Earth would be most nearly.
For this question I simply guessed. I knew "a" was 9.8 on the surface, and my answers were 0, 0.05, 5, 9, and 11, so I chose 9 and was right. Is there any algebraic/conceptual way to answer this besides my awesome guessing skills?
For this question I simply guessed. I knew "a" was 9.8 on the surface, and my answers were 0, 0.05, 5, 9, and 11, so I chose 9 and was right. Is there any algebraic/conceptual way to answer this besides my awesome guessing skills?
Answers
Answered by
bill j.
You are good! All you need is guessing skills for that problem.
Answered by
Hannah
THANK YOU!!! That pretty much tripled my physics self-esteem for the night :)
Answered by
bill j.
anytime
Answered by
bobpursley
The gravitaional field constant is proportional to the inverse of distance squared.
acceleartion= 9.8[ (6000km)/(6000km+300km)]^2
= 9.8 (1/(1+3/20) )^2= 9.8 (1/1.015)^2 close to your answer.
acceleartion= 9.8[ (6000km)/(6000km+300km)]^2
= 9.8 (1/(1+3/20) )^2= 9.8 (1/1.015)^2 close to your answer.
Answered by
bobpursley
correction
= 9.8/1.15^2
= 9.8/1.15^2
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