Asked by Tim
radius of the earth = 6.37 × 10^6
what is the speed of a 90.6 kg person at the equator?
I know that F=m(v^2/r) but I don't know the force. Is there another equation that I'm missing or I'm using the wrong one?
Thanks
what is the speed of a 90.6 kg person at the equator?
I know that F=m(v^2/r) but I don't know the force. Is there another equation that I'm missing or I'm using the wrong one?
Thanks
Answers
Answered by
drwls
They are not asking for the force. They want the speed due to the rotation of the earth. That equals R*w.
R is the earth radius and w is its rotation rate in radians per second.
R is the earth radius and w is its rotation rate in radians per second.
Answered by
Tim
How would I know W if that wasn't given?
Answered by
Tim
So I figured this out myself a=v^2/r
which is also equal to (4pi^2*r^2)/T^2
and T is 86400 secs which is how long it takes for a day to pass
which is also equal to (4pi^2*r^2)/T^2
and T is 86400 secs which is how long it takes for a day to pass
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