Asked by Anonymous

If f and g are linear functions such that g(f(x)) = 2x + 6, and the graph of y = f(g(x)) passes through the origin, what is the value of f(g(2011))?

Answers

Answered by MathMate
The question does not say that the coefficients of g(x) and f(x) are integers, so there may be many possible solutions.

One such solution is
f(x)=x+3
and
g(x)=2x
There is no constant term in g(x) because it passes through the origin.

This way g(f(x))=g(x+3)=2(x+3)=2x+6
and g(x) passes through the origin.

For this solution,
g(2011)=4022.
Answered by Steve
One solution is

f(x) = x+6
g(x) = 2x-6

so,

g(f) = 2f-6 = 2(x+6)-6 = 2x-6

Thus,

f(g) = g+6 = 2x
check:

f(g(0)) = f(-6) = -6+6 = 0
so f(g(x)) passes through (0,0)

f(g(2011)) = 2(2011) = 4022
Answered by maria
f(x)=3/2x-4022
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