Asked by Jackie
Consider the reaction:
3Ba(s)+N2(g)--->Ba3N2(s)
1)How many moles of barium metal react to produce 0.190 mol of barium nitride?
2)How many moles of nitrogen gas react?
3Ba(s)+N2(g)--->Ba3N2(s)
1)How many moles of barium metal react to produce 0.190 mol of barium nitride?
2)How many moles of nitrogen gas react?
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