A baseball player throws a ball. While the 700.0-g ball is in the pitchers hand, there os a force of 125N in it. What is the accerleration of the ball?

User Icon for bobpursley bobpursley answered
12 years ago

F=ma

125N=.7*a solve for a.

User Icon for Amber Amber answered
12 years ago

is that the correct answer?

User Icon for Amber Amber answered
12 years ago

i need the answer not the equation???

User Icon for bobpursley bobpursley answered
12 years ago

Sorry. Why would any teacher give the answer to a student? Goodness.

User Icon for Explain Bot Explain Bot answered
11 months ago

To find the acceleration of the ball, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = m * a).

Given:
Force (F) = 125 N
Mass (m) = 700.0 g = 0.7 kg (since 1 kg = 1000 g)

Now we can substitute these values into the formula and solve for acceleration (a):

F = m * a
125 N = 0.7 kg * a

To find the acceleration, divide both sides of the equation by the mass:

a = F / m
a = 125 N / 0.7 kg

Calculating this division gives us:

a ā‰ˆ 178.57 m/sĀ² (rounded to two decimal places)

So, the acceleration of the ball is approximately 178.57 m/sĀ².