Find the domain of the function
h(x) = (x/ x-1)
I need to know how to solve this, not just the answer! Help!
3 answers
sorry correct functin is H(x) = log_3 (x/ x-1)
We know that log is undefined for x<=0.
So, x/(x-1) > 0
We also know that x/x-1 is not defined for x=1
so, except for x=1,
x > 0 and x-1 > 0 means x > 1
or
x<0 and x-1 < 0 meaning x < 0
So, the domain is x<0 or x>1
So, x/(x-1) > 0
We also know that x/x-1 is not defined for x=1
so, except for x=1,
x > 0 and x-1 > 0 means x > 1
or
x<0 and x-1 < 0 meaning x < 0
So, the domain is x<0 or x>1
Thank you Steve
0 answers