Question
To determine the work function of a material of a photodiode, you measuered the maximum Knetic energy of .5 eV correwsponding to a certain wavelength. Later on, you cut down the wavelength by 50% and found the maximum kinetic energy of the photoelectrons to be 3.8eV. From this information determine
a) work function of the material, and
b) the original wavelength.
a) work function of the material, and
b) the original wavelength.
Answers
drwls
E1(max) = 0.5 eV = hc/L1 - phi
E2(max) = 3.8 eV = 2hc/L1 - phi
where
L1 = first wavelength
L1/2 = second wavelength
phi = work function
3.3 eV = hc/L1
b) Solve for L1 first
a) Then solve for phi
E2(max) = 3.8 eV = 2hc/L1 - phi
where
L1 = first wavelength
L1/2 = second wavelength
phi = work function
3.3 eV = hc/L1
b) Solve for L1 first
a) Then solve for phi